Puzzle for March 4, 2019  ( )

Scratchpad

Find the 6-digit number ABCDEF by solving the following equations:

eq.1) A + B + C + D + E + F = 27 eq.2) A = D + E eq.3) D + F = B eq.4) B + C = A + F eq.5) D + E = C + F eq.6) A - B = D ÷ F

A, B, C, D, E, and F each represent a one-digit non-negative integer.

Scratchpad

 

Help Area

Hint #1


In eq.4, replace B with D + F (from eq.3): D + F + C = A + F Subtract F from both sides of the above equation: D + F + C - F = A + F - F which becomes eq.4a) D + C = A


  

Hint #2


In eq.4a, replace A with D + E (from eq.2): D + C = D + E Subtract D from each side of the above equation: D + C - D = D + E - D which makes C = E


  

Hint #3


In eq.5, substitute C for E: D + C = C + F Subtract C from each side of the equation above: D + C - C = C + F - C which makes D = F


  

Hint #4


In eq.3, substitute F for D: F + F = B which makes 2×F = B


  

Hint #5


Substitute 2×F for B, and F for D in eq.6: A - 2×F = F ÷ F which means A - 2×F = 1 Add 2×F to each side of the equation above: A - 2×F + 2×F = 1 + 2×F which makes eq.6a) A = 1 + 2×F


  

Hint #6


Substitute F for D, and 1 + 2×F for A (from eq.6a) in eq.4a: F + C = 1 + 2×F Subtract F from each side: F + C - F = 1 + 2×F - F which means C = 1 + F which also means eq.4b) E = C = 1 + F


  

Solution

Substitute 1 + 2×F for A (from eq.6a), 2×F for B, 1 + F for C and E (from eq.4b), and F for D in eq.1: 1 + 2×F + 2×F + 1 + F + F + 1 + F + F = 27 which simplifies to 3 + 8×F = 27 Subtract 3 from each side of the above equation: 3 + 8×F - 3 = 27 - 3 which means 8×F = 24 Divide both sides by 8: 8×F ÷ 8 = 24 ÷ 8 which makes F = 3 making A = 1 + 2×F = 1 + 2×3 = 1 + 6 = 7 (from eq.6a) B = 2×F = 2×3 = 6 C = E = 1 + F = 1 + 3 = 4 (from eq.4b) D = F = 3 and ABCDEF = 764343