Puzzle for May 23, 2019  ( )

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Find the 6-digit number ABCDEF by solving the following equations:

eq.1) A + B + C + D + E + F = 24 eq.2) A + B = D eq.3) D + F = B + C eq.4) C + E = D - F eq.5) B = A + F eq.6) A + D + E = B + C + F

A, B, C, D, E, and F each represent a one-digit non-negative integer.

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Hint #1


In eq.3, replace D with A + B (from eq.2): A + B + F = B + C Subtract B from both sides of the above equation: A + B + F - B = B + C - B which becomes A + F = C Replace A + F with B (from eq.5) in the equation above: B = C


  

Hint #2


In eq.4, add F to each side, and subtract E from each side: C + E + F - E = D - F + F - E which becomes C + F = D - E In eq.6, replace C + F with D - E: A + D + E = B + D - E In the above equation, subtract D from each side, and add E to each side: A + D + E - D + E = B + D - E - D + E which becomes eq.6a) A + 2×E = B


  

Hint #3


In eq.5, substitute A + 2×E for B (from eq.6a): A + 2×E = A + F Subtract A from each side of the above equation: A + 2×E - A = A + F - A which becomes 2×E = F


  

Hint #4


Substitute 2×E for F in eq.4: C + E = D - 2×E Add 2×E to both sides of the equation above: C + E + 2×E = D - 2×E + 2×E which becomes eq.4a) C + 3×E = D


  

Hint #5


Substitute C + 3×E for D (from eq.4a), 2×E for F, and C for B in eq.3: C + 3×E + 2×E = C + C which becomes C + 5×E = 2×C Subtract C from both sides: C + 5×E - C = 2×C - C which makes 5×E = C which also makes B = C = 5×E


  

Hint #6


Substitute 5×E for B in eq.6a: A + 2×E = 5×E Subtract 2×E from both sides: A + 2×E - 2×E = 5×E - 2×E which means A = 3×E


  

Hint #7


Substitute 5×E for C in eq.4a: 5×E + 3×E = D which means 8×E = D


  

Solution

Substitute 3×E for A, 5×E for B and C, 8×E for D, and 2×E for F in eq.1: 3×E + 5×E + 5×E + 8×E + E + 2×E = 24 which simplifies to 24×E = 24 Divide both sides of the above equation by 24: 24×E ÷ 24 = 24 ÷ 24 which means E = 1 making A = 3×E = 3 × 1 = 3 B = C = 5×E = 5 × 1 = 5 D = 8×E = 8 × 1 = 8 F = 2×E = 2 × 1 = 2 and ABCDEF = 355812