Puzzle for July 5, 2019  ( )

Scratchpad

Find the 6-digit number ABCDEF by solving the following equations:

eq.1) A + B + C + D + E + F = 26 eq.2) A = B + D eq.3) D = E - F - A eq.4) C - D = E + F - B eq.5) B - C - F = A + D - E eq.6) F - C = D - B

A, B, C, D, E, and F each represent a one-digit non-negative integer.

Scratchpad

 

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Hint #1


Add A and F to both sides of eq.3: D + A + F = E - F - A + A + F which becomes D + A + F = E which may be written as eq.3a) A + D + F = E


  

Hint #2


Add E and F to both sides of eq.5: B - C - F + E + F = A + D - E + E + F which becomes B - C + E = A + D + F In the above equation, replace A + D + F with E (from eq.3a): B - C + E = E Subtract E from both sides, and add C to both sides: B - C + E - E + C = E - E + C which simplifies to B = C


  

Hint #3


In eq.6, replace C with B: F - B = D - B Add B to both sides of the above equation: F - B + B = D - B + B which makes F = D


  

Hint #4


In eq.4, substitute B for C, and D for F: B - D = E + D - B Add B and D to both sides of the above equation: B - D + B + D = E + D - B + B + D eq.4a) 2×B = E + 2×D


  

Hint #5


In eq.3a, substitute B + D for A (from eq.2), and D for F: B + D + D + D = E which becomes eq.5a) B + 3×D = E


  

Hint #6


Substitute B + 3×D for E (from eq.5a) in eq.4a: 2×B = B + 3×D + 2×D which becomes 2×B = B + 5×D Subtract B from both sides of the above equation: 2×B - B = B + 5×D - B which makes B = 5×D and which also makes C = B = 5×D


  

Hint #7


Substitute 5×D for B in eq.2: A = 5×D + D which makes A = 6×D


  

Hint #8


Substitute 5×D for B in eq.5a: 5×D + 3×D = E which makes 8×D = E


  

Solution

Substitute 6×D for A, 5×D for B and C, 8×D for E, and D for F in eq.1: 6×D + 5×D + 5×D + D + 8×D + D = 26 which simplifies to 26×D = 26 Divide both sides of the above equation by 26: 26×D ÷ 26 = 26 ÷ 26 which means D = 1 making A = 6×D = 6×1 = 6 B = C = 5×D = 5×1 = 5 E = 8×D = 8×1 = 8 F = D = 1 and ABCDEF = 655181