Puzzle for July 11, 2019  ( )

Scratchpad

Find the 6-digit number ABCDEF by solving the following equations:

eq.1) A + B + C + D + E + F = 29 eq.2) E + F = A + B + C eq.3) F = C + D eq.4) A + F = C - D + E eq.5) B - C = F - E eq.6) C = A - D

A, B, C, D, E, and F each represent a one-digit non-negative integer.

Scratchpad

 

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Hint #1


In eq.3, replace C with A - D (from eq.6): F = A - D + D which makes F = A   In eq.3, replace F with A: eq.3a) A = C + D


  

Hint #2


In eq.2, replace A with F: E + F = F + B + C Subtract F from both sides of the above equation: E + F - F = F + B + C - F which becomes eq.2a) E = B + C


  

Hint #3


In eq.4, substitute C + D for A (from eq.3a) and for F (from eq.3): C + D + C + D = C - D + E which becomes 2×C + 2×D = C - D + E In the above equation, subtract C from both sides, and add D to both sides: 2×C + 2×D - C + D = C - D + E - C + D which simplifies to eq.4a) C + 3×D = E


  

Hint #4


Substitute C + 3×D for E (from eq.4a) in eq.2a: C + 3×D = B + C Subtract C from both sides of the above equation: C + 3×D - C = B + C - C which makes 3×D = B


  

Hint #5


In eq.5, substitute (B + C) for E (from eq.2a): B - C = F - (B + C) which is the same as B - C = F - B - C Add B and C to both sides of the above equation: B - C + B + C = F - B - C + B + C which simplifies to eq.2b) 2×B = F


  

Hint #6


Substitute (3×D) for B in eq.2b: 2×(3×D) = F which makes 6×D = F and also makes A = F = 6×D


  

Hint #7


Substitute 6×D for F in eq.3: 6×D = C + D Subtract D from both sides: 6×D - D = C + D - D which makes 5×D = C


  

Hint #8


Substitute 3×D for B, and 5×D for C in eq.2a: E = 3×D + 5×D which makes E = 8×D


  

Solution

Substitute 6×D for A and F, 3×D for B, 5×D for C, and 8×D for E in eq.1: 6×D + 3×D + 5×D + D + 8×D + 6×D = 29 which simplifies to 29×D = 29 Divide both sides of the above equation by 29: 29×D ÷ 29 = 29 ÷ 29 which means D = 1 making A = F = 6×D = 6×1 = 6 B = 3×D = 3×1 = 3 C = 5×D = 5×1 = 5 E = 8×D = 8×1 = 8 and ABCDEF = 635186