Puzzle for August 19, 2019  ( )

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Find the 6-digit number ABCDEF by solving the following equations:

eq.1) A + B + C + D + E + F = 28 eq.2) D + E = A + B + C eq.3) B + D = C + F eq.4) F = B + C eq.5) D = A + C eq.6) E = C + D

A, B, C, D, E, and F each represent a one-digit non-negative integer.

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Hint #1


In eq.3, replace F with B + C (from eq.4): B + D = C + B + C which becomes B + D = B + 2×C Subtract B from both sides of the above equation: B + D – B = B + 2×C – B which makes D = 2×C


  

Hint #2


In eq.5, replace D with 2×C: 2×C = A + C Subtract C from each side of the equation above: 2×C – C = A + C – C which makes C = A


  

Hint #3


In eq.6, substitute 2×C for D: E = C + 2×C which makes E = 3×C


  

Hint #4


Substitute 2×C for D, 3×C for E, and C for A in eq.2: 2×C + 3×C = C + B + C which becomes 5×C = B + 2×C Subtract 2×C from each side of the above equation: 5×C – 2×C = B + 2×C – 2×C which makes 3×C = B


  

Hint #5


Substitute 3×C for B in eq.4: F = 3×C + C which means F = 4×C


  

Solution

Substitute C for A, 3×C for B and E, 2×C for D, and 4×C for F in eq.1: C + 3×C + C + 2×C + 3×C + 4×C = 28 which simplifies to 14×C = 28 Divide both sides of the equation above by 14: 14×C ÷ 14 = 28 ÷ 14 which means C = 2 making A = C = 2 B = E = 3×C = 3 × 2 = 6 D = 2×C = 2 × 2 = 4 F = 4×C = 4 × 2 = 8 and ABCDEF = 262468