Puzzle for December 25, 2019  ( )

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Find the 6-digit number ABCDEF by solving the following equations:

eq.1) A + B + C + D + E + F = 35 eq.2) B – E = A eq.3) E + F = B + C eq.4) A + C + D = B + E eq.5) B + D – E = A + F eq.6) C + E – A = A + D

A, B, C, D, E, and F each represent a one-digit non-negative integer.

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Hint #1


In eq.5, replace A with B – E (from eq.2): B + D – E = B – E + F In the above equation, subtract B from both sides, and add E to each side: B + D – E – B + E = B – E + F – B + E which simplifies to D = F


  

Hint #2


Add E to both sides of eq.2: B – E + E = A + E which becomes B = A + E In eq.3, replace F with D, and B with A + E: E + D = A + E + C Subtract E from both sides of the above equation: A + E + C – E = E + D – E which becomes eq.3a) A + C = D


  

Hint #3


Substitute A + C for D (from eq.3a) in eq.6: C + E – A = A + A + C In the above equation, add A to both sides, and subtract C from each side:: C + E – C – A + A = A + A + C + A – C which makes E = 3×A


  

Hint #4


Substitute 3×A for E in eq.2: B – 3×A = A Add 3×A to both sides of the equation above: B – 3×A + 3×A = A + 3×A which makes B = 4×A


  

Hint #5


Substitute A + C for D (from eq.3a), 4×A for B, and 3×A for E in eq.4: A + C + A + C = 4×A + 3×A which becomes 2×A + 2×C = 7×A Subtract 2×A from both sides of the equation above: 2×A + 2×C – 2×A = 7×A – 2×A which makes 2×C = 5×A Divide both sides by 2: 2×C ÷ 2 = 5×A ÷ 2 which means C = 2½×A


  

Hint #6


Substitute 2½×A for C in eq.3a: A + 2½×A = D which makes 3½×A = D and also makes F = D = 3½×A


  

Solution

Substitute 4×A for B, 2½×A for C, 3½×A for D and F, and 3×A for E in eq.1: A + 4×A + 2½×A + 3½×A + 3×A + 3½×A = 35 which simplifies to 17½×A = 35 Divide both sides of the above equation by 17½: 17½×A ÷ 17½ = 35 ÷ 17½ which means A = 2 making B = 4×A = 4 × 2 = 8 C = 2½×A = 2½ × 2 = 5 D = F = 3½×A = 3½ × 2 = 7 E = 3×A = 3 × 2 = 6 and ABCDEF = 285767