Puzzle for June 1, 2020  ( )

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Find the 6-digit number ABCDEF by solving the following equations:

eq.1) A + B + C + D + E + F = 17 eq.2) F = A + B eq.3) D + E = A + B + C eq.4) A + D = C + E + F eq.5) B = A + E eq.6) C + E = A

A, B, C, D, E, and F each represent a one-digit non-negative integer.

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Hint #1


In eq.4, replace C + E with A (from eq.6): A + D = A + F Subtract A from both sides of the above equation: A + D – A = A + F – A which makes D = F


  

Hint #2


In eq.3, replace D with F, and A + B with F (from eq.2): F + E = F + C Subtract F from each side of the above equation: F + E – F = F + C – F which makes E = C


  

Hint #3


In eq.6, substitute C for E: C + C = A which makes 2×C = A


  

Hint #4


Substitute 2×C for A, and C for E in eq.5: B = 2×C + C which makes B = 3×C


  

Hint #5


Substitute 2×C for A, and 3×C for B in eq.2: F = 2×C + 3×C which makes F = 5×C and also makes D = F = 5×C


  

Solution

Substitute 2×C for A, 3×C for B, 5×C for D and F, and C for E in eq.1: 2×C + 3×C + C + 5×C + C + 5×C = 17 which simplifies to 17×C = 17 Divide both sides of the above equation by 17: 17×C ÷ 17 = 17 ÷ 17 which means C = 1 making A = 2×C = 2 B = 3×C = 3 D = F = 5×C = 5 E = C = 1 and ABCDEF = 231515