Puzzle for October 26, 2020  ( )

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Find the 6-digit number ABCDEF by solving the following equations:

eq.1) A + B + C + D + E + F = 35 eq.2) F = A + B eq.3) B – C + E + F = A + C eq.4) D + E = B – D + F eq.5) E = A + D eq.6) F – A = A + D

A, B, C, D, E, and F each represent a one-digit non-negative integer.

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Hint #1


In eq.6, replace F with A + B (from eq.2), and A + D with E (from eq.5): A + B – A = E which makes B = E


  

Hint #2


In eq.4, replace E with B: D + B = B – D + F In the above equation, subtract B from both sides, and add D to both sides: D + B – B + D = B – D + F – B + D which makes eq.4a) 2×D = F


  

Hint #3


In eq.6, substitute 2×D for F: 2×D – A = A + D In the above equation, add A to both sides, and subtract D from both sides: 2×D – A + A – D = A + D + A – D which makes D = 2×A


  

Hint #4


Substitute (2×A) for D in eq.4a: 2×(2×A) = F which makes 4×A = F


  

Hint #5


Substitute 2×A for D in eq.5: E = A + 2×A which makes E = 3×A and also makes B = E = 3×A


  

Hint #6


Substitute 3×A for B and E, and 4×A for F in eq.3: 3×A – C + 3×A + 4×A = A + C which becomes 10×A – C = A + C In the above equation, add C to both sides, and subtract A from both sides: 10×A – C + C – A = A + C + C – A which makes 9×A = 2×C Divide both sides by 2: 9×A ÷ 2 = 2×C ÷ 2 which makes 4½×A = C


  

Solution

Substitute 3×A for B and E, 4½×A for C, 2×A for D, and 4×A for F in eq.1: A + 3×A + 4½×A + 2×A + 3×A + 4×A = 35 which simplifies to 17½×A = 35 Divide both sides of the equation above by 17½: 17½×A ÷ 17½ = 35 ÷ 17½ which means A = 2 making B = E = 3×A = 3 × 2 = 6 C = 4½×A = 4½ × 2 = 9 D = 2×A = 2 × 2 = 4 F = 4×A = 4 × 2 = 8 and ABCDEF = 269468