Puzzle for December 15, 2020  ( )

Scratchpad

Find the 6-digit number ABCDEF by solving the following equations:

eq.1) A + B + C + D + E + F = 36 eq.2) B + E = D eq.3) C + F = D + E eq.4) E + F = A + B + C eq.5) F – B = A + B eq.6) D ÷ C = B

A, B, C, D, E, and F each represent a one-digit non-negative integer.

Scratchpad

 

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Hint #1


In eq.4, replace A + B with F – B (from eq.5): E + F = F – B + C In the above equation, subtract F from both sides, and add B to both sides: E + F – F + B = F – B + C – F + B which becomes E + B = C which is the same as eq.4a) B + E = C


  

Hint #2


In eq.2, replace B + E with C (from eq.2): C = D


  

Hint #3


In eq.3, substitute C for D: C + F = C + E Subtract C from each side of the equation above: C + F – C = C + E – C which makes F = E


  

Hint #4


Substitute C for D in eq.6: C ÷ C = B which makes 1 = B


  

Hint #5


Substitute 1 for B in eq.4a: 1 + E = C which also makes eq.4b) D = C = 1 + E


  

Hint #6


Substitute E for F, and 1 for B in eq.5: E – 1 = A + 1 Subtract 1 from each side of the above equation: E – 1 – 1 = A + 1 – 1 which makes eq.5a) E – 2 = A


  

Solution

Substitute E – 2 for A (from eq.5a), 1 for B, 1 + E for C and D (from eq.4b), and E for F in eq.1: E – 2 + 1 + 1 + E + 1 + E + E + E = 36 which simplifies to 5×E + 1 = 36 Subtract 1 from each side of the above equation: 5×E + 1 – 1 = 36 – 1 which makes 5×E = 35 Divide both sides by 5: 5×E ÷ 5 = 35 ÷ 5 which means E = 7 making A = E – 2 = 7 – 2 = 5 (from eq.5a) C = D = 1 + E = 1 + 7 = 8 (from eq.4b) F = E = 7 and ABCDEF = 518877