Puzzle for August 9, 2021  ( )

Scratchpad

Find the 6-digit number ABCDEF by solving the following equations:

eq.1) A + B + C + D + E + F = 24 eq.2) D = B + C eq.3) E = A + C eq.4) A = C + F eq.5) C + E = A + F eq.6) E – B = A + B

A, B, C, D, E, and F each represent a one-digit non-negative integer.

Scratchpad

 

Help Area

Hint #1


In eq.5, replace E with A + C (from eq.3): C + A + C = A + F which becomes 2×C + A = A + F Subtract A from each side of the equation above: 2×C + A – A = A + F – A which makes 2×C = F


  

Hint #2


In eq.4, replace F with 2×C: A = C + 2×C which makes A = 3×C


  

Hint #3


In eq.3, substitute 3×C for A: E = 3×C + C which makes E = 4×C


  

Hint #4


Substitute 4×C for E, and 3×C for A in eq.6: 4×C – B = 3×C + B In the above equation, add B to both sides, and subtract 3×C from both sides: 4×C – B + B – 3×C = 3×C + B + B – 3×C which makes C = 2×B Divide both sides by 2: C ÷ 2 = 2×B ÷ 2 which makes ½×C = B


  

Hint #5


Substitute ½×C for B in eq.2: D = ½×C + C which makes D = 1½×C


  

Solution

Substitute 3×C for A, ½×C for B, 1½×C for D, 4×C for E, and 2×C for F in eq.1: 3×C + ½×C + C + 1½×C + 4×C + 2×C = 24 which simplifies to 12×C = 24 Divide both sides of the above equation by 12: 12×C ÷ 12 = 24 ÷ 12 which means C = 2 making A = 3×C = 3 × 2 = 6 B = ½×C = ½ × 2 = 1 D = 1½×C = 1½ × 2 = 3 E = 4×C = 4 × 2 = 8 F = 2×C = 2 × 2 = 4 and ABCDEF = 612384