Puzzle for October 4, 2021  ( )

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Find the 6-digit number ABCDEF by solving the following equations:

eq.1) A + B + C + D + E + F = 30 eq.2) B + E = C eq.3) D + E = B eq.4) C + F = A eq.5) E + F = D – F eq.6) A – E = C + E

A, B, C, D, E, and F each represent a one-digit non-negative integer.

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Hint #1


In eq.6, replace A with C + F (from eq.4): C + F – E = C + E In the equation above, subtract C from both sides, and add E to both sides: C + F – E – C + E = C + E – C + E which makes F = 2×E


  

Hint #2


In eq.5, replace F with 2×E: E + 2×E = D – 2×E which becomes 3×E = D – 2×E Add 2×E to both sides of the above equation: 3×E + 2×E = D – 2×E + 2×E which makes 5×E = D


  

Hint #3


In eq.3, substitute 5×E for D: 5×E + E = B which makes 6×E = B


  

Hint #4


Substitute 6×E for B in eq.2: 6×E + E = C which makes 7×E = C


  

Hint #5


Substitute 7×E for C, and 2×E for F in eq.4: 7×E + 2×E = A which makes 9×E = A


  

Solution

Substitute 9×E for A, 6×E for B, 7×E for C, 5×E for D, and 2×E for F in eq.1: 9×E + 6×E + 7×E + 5×E + E + 2×E = 30 which simplifies to 30×E = 30 Divide both sides of the above equation by 30: 30×E ÷ 30 = 30 ÷ 30 which means E = 1 making A = 9×E = 9 × 1 = 9 B = 6×E = 6 × 1 = 6 C = 7×E = 7 × 1 = 7 D = 5×E = 5 × 1 = 5 F = 2×E = 2 × 1 = 2 and ABCDEF = 967512