Puzzle for November 23, 2021  ( )

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Find the 6-digit number ABCDEF by solving the following equations:

eq.1) A + B + C + D + E + F = 25 eq.2) A = D + E eq.3) B = C + D eq.4) C = D + E + F eq.5) A + E = C – E eq.6) D + E = F – D

A, B, C, D, E, and F each represent a one-digit non-negative integer.

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Hint #1


In eq.5, replace A with D + E (from eq.2): D + E + E = C – E which becomes D + 2×E = C – E Add E to both sides of the above equation: D + 2×E + E = C – E + E which becomes eq.5a) D + 3×E = C


  

Hint #2


In eq.4, replace C with D + 3×E (from eq.5a): D + 3×E = D + E + F Subtract D and E from both sides of the above equation: D + 3×E – D – E = D + E + F – D – E which simplifies to eq.4a) 2×E = F


  

Hint #3


In eq.6, substitute 2×E for F: D + E = 2×E – D In the equation above, subtract E from both sides, and add D to both sides: D + E – E + D = 2×E – D – E + D which makes 2×D = E


  

Hint #4


Substitute (2×D) for E into eq.4a: 2×(2×D) = F which makes 4×D = F


  

Hint #5


Substitute (2×D) for E in eq.5a: D + 3×(2×D) = C which becomes D + 6×D = C which makes 7×D = C


  

Hint #6


Substitute 2×D for E in eq.2: A = D + 2×D which makes A = 3×D


  

Hint #7


Substitute 7×D for C in eq.3: B = 7×D + D which makes B = 8×D


  

Solution

Substitute 3×D for A, 8×D for B, 7×D for C, 2×D for E, and 4×D for F in eq.1: 3×D + 8×D + 7×D + D + 2×D + 4×D = 25 which simplifies to 25×D = 25 Divide both sides of the above equation by 25: 25×D ÷ 25 = 25 ÷ 25 which means D = 1 making A = 3×D = 3 × 1 = 3 B = 8×D = 8 × 1 = 8 C = 7×D = 7 × 1 = 7 E = 2×D = 2 × 1 = 2 F = 4×D = 4 × 1 = 4 and ABCDEF = 387124