Puzzle for May 3, 2022  ( )

Scratchpad

Find the 6-digit number ABCDEF by solving the following equations:

eq.1) A + B + C + D + E + F = 29 eq.2) C + D = B – E eq.3) A + C = B + E eq.4) D – C = A – E eq.5) F = (B + C + D) ÷ A

A, B, C, D, E, and F each represent a one-digit non-negative integer.

Scratchpad

 

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Hint #1


Add E to both sides of eq.2: C + D + E = B – E + E which becomes eq.2a) C + D + E = B   Add E to both sides of eq.4: D – C + E = A – E + E which becomes eq.4a) D – C + E = A


  

Hint #2


In eq.3, replace A with D – C + E (from eq.4a), and B with C + D + E (from eq.2a): D – C + E + C = C + D + E + E which becomes D + E = C + D + 2×E Subtract D and E from each side of the equation above: D + E – D – E = C + D + 2×E – D – E which simplifies to eq.3a) 0 = C + E


  

Hint #3


Since C and E must be non-negative, eq.3a makes: C = 0 and E = 0


  

Hint #4


Substitute 0 for C and E in eq.2: 0 + D = B – 0 which makes D = B


  

Hint #5


Substitute 0 for C and E in eq.3: A + 0 = B + 0 which makes A = B and also makes A = B = D


  

Hint #6


Substitute A for B and D, and 0 for C in eq.5: F = (A + 0 + A) ÷ A which becomes F = 2×A ÷ A which makes F = 2


  

Solution

Substitute A for B and D, 0 for C and E, and 2 for F in eq.1: A + A + 0 + A + 0 + 2 = 29 which becomes 3×A + 2 = 29 Subtract 2 from each side of the above equation: 3×A + 2 – 2 = 29 – 2 which makes 3×A = 27 Divide both sides by 3: 3×A ÷ 3 = 27 ÷ 3 which means A = 9 making B = D = A = 9 and ABCDEF = 990902