Puzzle for June 13, 2022  ( )

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Find the 6-digit number ABCDEF by solving the following equations:

eq.1) A + B + C + D + E + F = 25 eq.2) A = C + D eq.3) B = A + F eq.4) C = E + F eq.5) D = C + F eq.6) C + E = D + F

A, B, C, D, E, and F each represent a one-digit non-negative integer.

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Hint #1


In eq.6, replace D with C + F (from eq.5): C + E = C + F + F which becomes C + E = C + 2×F Subtract C from each side of the equation above: C + E – C = C + 2×F – C which makes E = 2×F


  

Hint #2


In eq.4, replace E with 2×F: C = 2×F + F which makes C = 3×F


  

Hint #3


In eq.5, substitute 3×F for C: D = 3×F + F which makes D = 4×F


  

Hint #4


In eq.2, substitute 3×F for C, and 4×F for D: A = 3×F + 4×F which makes A = 7×F


  

Hint #5


Substitute 7×F for A in eq.3: B = 7×F + F which makes B = 8×F


  

Solution

Substitute 7×F for A, 8×F for B, 3×F for C, 4×F for D, and 2×F for E in eq.1: 7×F + 8×F + 3×F + 4×F + 2×F + F = 25 which simplifies to 25×F = 25 Divide both sides of the above equation by 25: 25×F ÷ 25 = 25 ÷ 25 which means F = 1 making A = 7×F = 7 × 1 = 7 B = 8×F = 8 × 1 = 8 C = 3×F = 3 × 1 = 3 D = 4×F = 4 × 1 = 4 E = 2×F = 2 × 1 = 2 and ABCDEF = 783421