Puzzle for October 24, 2022  ( )

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Find the 6-digit number ABCDEF by solving the following equations:

eq.1) A + B + C + D + E + F = 24 eq.2) D = A + B eq.3) F = C + E eq.4) B = A + C eq.5) D - C = A + C eq.6) E - B = A + B + D

A, B, C, D, E, and F each represent a one-digit non-negative integer.

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Hint #1


In eq.5, replace D with A + B (from eq.2): A + B - C = A + C In the above equation, subtract A from both sides, and add C to both sides: A + B - C - A + C = A + C - A + C which makes B = 2×C


  

Hint #2


In eq.4, replace B with 2×C: 2×C = A + C Subtract C from each side of the equation above: 2×C - C = A + C - C which makes C = A


  

Hint #3


In eq.2, substitute C for A, and 2×C for B: D = C + 2×C which becomes D = 3×C


  

Hint #4


Substitute 2×C for B, C for A, and 3×C for D in eq.6: E - 2×C = C + 2×C + 3×C which becomes E - 2×C = 6×C Add 2×C to both sides of the equation above: E - 2×C + 2×C = 6×C + 2×C which makes E = 8×C


  

Hint #5


Substitute 8×C for E in eq.3: F = C + 8×C which makes F = 9×C


  

Solution

Substitute C for A, 2×C for B, 3×C for D, 8×C for E, and 9×C for F in eq.1: C + 2×C + C + 3×C + 8×C + 9×C = 24 which simplifies to 24×C = 24 Divide both sides of the above equation by 24: 24×C ÷ 24 = 24 ÷ 24 which means C = 1 making A = C = 1 B = 2×C = 2 × 1 = 2 D = 3×C = 3 × 1 = 3 E = 8×C = 8 × 1 = 8 F = 9×C = 9 × 1 = 9 and ABCDEF = 121389