Puzzle for June 3, 2023  ( )

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Find the 6-digit number ABCDEF by solving the following equations:

eq.1) A + B + C + D + E + F = 21 eq.2) B - F = A - B eq.3) D + F = B + C eq.4) C - A = A - D + E eq.5) E + F - B = B + C - F eq.6) A + B + C = D + E + F - C

A, B, C, D, E, and F each represent a one-digit non-negative integer.

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Hint #1


Add B and F to both sides of eq.2: B - F + B + F = A - B + B + F which becomes eq.2a) 2×B = A + F   Add B and F to both sides of eq.5: E + F - B + B + F = B + C - F + B + F which becomes eq.5a) E + 2×F = 2×B + C


  

Hint #2


In eq.5a, replace 2×B with A + F (from eq.2a): E + 2×F = A + F + C Subtract F from each side of the equation above: E + 2×F - F = A + F + C - F which becomes eq.5b) E + F = A + C


  

Hint #3


In eq.6, replace E + F with A + C (from eq.5b): A + B + C = D + A + C - C which becomes A + B + C = D + A Subtract A from both sides of the equation above: A + B + C - A = D + A - A which becomes eq.6a) B + C = D


  

Hint #4


In eq.3, substitute D for B + C (from eq.6a): D + F = D Subtract D from each side of the equation above: D + F - D = D - D which makes F = 0


  

Hint #5


Substitute 0 for F in eq.2a: 2×B = A + 0 which makes 2×B = A


  

Hint #6


Substitute 2×B for A in eq.4: C - 2×B = 2×B - D + E Add 2×B to both sides of the above equation: C - 2×B + 2×B = 2×B - D + E + 2×B which becomes eq.4a) C = 4×B - D + E


  

Hint #7


Substitute 0 for F, and 2×B for A in eq.5b: E + 0 = 2×B + C which becomes eq.5c) E = 2×B + C


  

Hint #8


Substitute 2×B + C for E (from eq.5c) in eq.4a: C = 4×B - D + 2×B + C which becomes C = 6×B - D + C In the equation above, subtract C from both sides, and add D to both sides: C - C + D = 6×B - D + C - C + D which makes D = 6×B


  

Hint #9


Substitute 6×B for D in eq.6a: B + C = 6×B Subtract B from each side of the above equation: B + C - B = 6×B - B which makes C = 5×B


  

Hint #10


Substitute 5×B for C in eq.5c: E = 2×B + 5×B which makes E = 7×B


  

Solution

Substitute 2×B for A, 5×B for C, 6×B for D, 7×B for E, and 0 for F in eq.1: 2×B + B + 5×B + 6×B + 7×B + 0 = 21 which simplifies to 21×B = 21 Divide both sides of the above equation by 21: 21×B ÷ 21 = 21 ÷ 21 which means B = 1 making A = 2×B = 2 × 1 = 2 C = 5×B = 5 × 1 = 5 D = 6×B = 6 × 1 = 6 E = 7×B = 7 × 1 = 7 and ABCDEF = 215670