Puzzle for August 9, 2023  ( )

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Find the 6-digit number ABCDEF by solving the following equations:

eq.1) A + B + C + D + E + F = 26 eq.2) B - A = A - C eq.3) E + F = B + C eq.4) D + F = A + E eq.5) B + D = A + E + F eq.6) C + E + F = B - C + D

A, B, C, D, E, and F each represent a one-digit non-negative integer.

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Hint #1


eq.6 may be written as: C + E + F = B + D - C In the above equation, replace B + D with A + E + F (from eq.5): C + E + F = A + E + F - C In the equation above, subtract E and F from both sides, and add C to both sides: C + E + F - E - F + C = A + E + F - C - E - F + C which simplifies to 2×C = A


  

Hint #2


In eq.2, replace A with 2×C: B - 2×C = 2×C - C which becomes B - 2×C = C Add 2×C to both sides of the above equation: B - 2×C + 2×C = C + 2×C which makes B = 3×C


  

Hint #3


In eq.3, substitute 3×C for B: E + F = 3×C + C which becomes eq.3a) E + F = 4×C


  

Hint #4


Substitute 4×C for E + F (from eq.3a), and 3×C for B in eq.6: C + 4×C = 3×C - C + D which becomes 5×C = 2×C + D Subtract 2×C from each side of the equation above: 5×C - 2×C = 2×C + D - 2×C which makes 3×C = D


  

Hint #5


Subtract F from both sides of eq.3a: E + F - F = 4×C - F which becomes eq.3b) E = 4×C - F


  

Hint #6


Substitute 3×C for D, 2×C for A, and 4×C - F for E (from eq.3b) in eq.4: 3×C + F = 2×C + 4×C - F which becomes 3×C + F = 6×C - F In the equation above, subtract 3×C from both sides, and add F to both sides: 3×C + F - 3×C + F = 6×C - F - 3×C + F which becomes 2×F = 3×C Divide both sides by 2: 2×F ÷ 2 = 3×C ÷ 2 which makes F = 1½×C


  

Hint #7


Substitute 1½×C for F in eq.3b: E = 4×C - 1½×C which makes E = 2½×C


  

Solution

Substitute 2×C for A, 3×C for B and D, 2½×C for E, and 1½×C for F in eq.1: 2×C + 3×C + C + 3×C + 2½×C + 1½×C = 26 which simplifies to 13×C = 26 Divide both sides of the above equation by 13: 13×C ÷ 13 = 26 ÷ 13 which means C = 2 making A = 2×C = 2 × 2 = 4 B = D = 3×C = 3 × 2 = 6 E = 2½×C = 2½ × 2 = 5 F = 1½×C = 1½ × 2 = 3 and ABCDEF = 462653