Puzzle for October 9, 2023  ( )

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Find the 6-digit number ABCDEF by solving the following equations:

eq.1) A + B + C + D + E + F = 27 eq.2) C = D + F eq.3) F = A + B + D eq.4) B + F = C + D eq.5) A - D = B + D eq.6) D + E = A + B

A, B, C, D, E, and F each represent a one-digit non-negative integer.

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Hint #1


In eq.4, replace C with D + F (from eq.2): B + F = D + F + D which becomes B + F = 2×D + F Subtract F from each side of the equation above: B + F - F = 2×D + F - F which makes B = 2×D


  

Hint #2


In eq.5, replace B with 2×D: A - D = 2×D + D which becomes A - D = 3×D Add D to each side of the above equation: A - D + D = 3×D + D which makes A = 4×D


  

Hint #3


In eq.6, substitute 4×D for A, and 2×D for B: D + E = 4×D + 2×D which becomes D + E = 6×D Subtract D from both sides of the above equation: D + E - D = 6×D - D which makes E = 5×D


  

Hint #4


In eq.3, substitute 4×D for A, and 2×D for B: F = 4×D + 2×D + D which makes F = 7×D


  

Hint #5


Substitute 7×D for F in eq.2: C = D + 7×D which makes C = 8×D


  

Solution

Substitute 4×D for A, 2×D for B, 8×D for C, 5×D for E, and 7×D for F in eq.1: 4×D + 2×D + 8×D + D + 5×D + 7×D = 27 which simplifies to 27×D = 27 Divide both sides of the above equation by 27: 27×D ÷ 27 = 27 ÷ 27 which means D = 1 making A = 4×D = 4 × 1 = 4 B = 2×D = 2 × 1 = 2 C = 8×D = 8 × 1 = 8 E = 5×D = 5 × 1 = 5 F = 7×D = 7 × 1 = 7 and ABCDEF = 428157